Ok maybe this has been answered before but why is the G30 SoC more expensive than the G30 TH module? That seems backwards to conventional logic.You have to buy 100+ G30 SoC to get below the price of the TH module… which has the G30 SoC and a bunch of other stuff on a PCB. 
Both products are extremely cheap, no matter which one cost a dollar more
Still, we need to investigate this
Well it would be nice if the G30 SoC were to drop in price instead of something going up, but I understand if economics don’t fit the model.
I was just wondering if it is possible to get some empty G30TH-PCBs? I have three lonely G30s lying around, that weren’t used, because I decided to use a G120 with Wifi instead. I’d like to do something useful like putting them on breadboards or something 
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Search the web for lqfp breakout. This maybe a good option.
While it’s not populated, I’ve used this company before for breakout boards. I actually have one of theirs sitting on my bench right now running a long term test of an LTC2495 chip.
http://www.proto-advantage.com/store/product_info.php?products_id=2200113
You can order them already populated with a digikey part #, they’ll do the soldering and assembly for you. However, I hand tinned my own and reflowed with a reflow station since I already had the IC’s I was going to mount here.
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which is the perfect number for a one-off OSHPark PCB order. The Schematic isn’t very complex so I suspect an hour or so in a PCB program would turn that into a decent board. That is, if you didn’t want to look at the other simple breakout options.
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Speaking of breakouts, what’s the deal with the two crystal symbols here on the G30 TH schematic?
Q1A and Q1B
Doesn’t it need a single 12mhz crystal resonator? If there’s two there what’s the value on Q1A?
And Q1 = ?? 32k?
I’d say Q1A and Q1B are the same crystals with two different footprints, so a wider variety of crystals can be used, depending on availability and prices on the market.
The 32k-Crystal Q1 is the one for the RTC.
The value of C6-C9 depend on the crystal you use (mostly twice the loading-capacity of your crystal).
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